3x^2=18+3/4

Solution for 3x^2=18+3/4 equation:

3x^2=18+3/4

We move all terms to the left:

3x^2-(18+3/4)=0

We add all the numbers together, and all the variables

3x^2-(3/4+18)=0

We get rid of parentheses

3x^2-18-3/4=0

We multiply all the terms by the denominator


3x^2*4-3-18*4=0

We add all the numbers together, and all the variables

3x^2*4-75=0

Wy multiply elements

12x^2-75=0

a = 12; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·12·(-75)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*12}=\frac{-60}{24}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*12}=\frac{60}{24}
=2+1/2
$